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sjalloq  
#1 Posted : Monday, June 15, 2009 9:11:44 AM(UTC)
sjalloq

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Hi there,

I noticed that you guys recommend a 470uF filter capacitor for use with the 7805 on the relay driver board. I thought this seemed too low so can I check if it's a typo or not (was it meant to be 4700uF)? If not, then what is the current draw for two relay boards in a ballanced system?

Thanks a lot.
Brian Donegan  
#2 Posted : Monday, June 15, 2009 9:32:05 AM(UTC)
Brian Donegan

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Que?

I actually ship 220uF in the kit...

470uF is fine. Relay coils are not that picky.

Edited by user Monday, June 15, 2009 9:32:37 AM(UTC)  | Reason: Not specified

Russ White  
#3 Posted : Monday, June 15, 2009 9:33:46 AM(UTC)
Russ White

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And it regulated prior to them. :)
sjalloq  
#4 Posted : Monday, June 15, 2009 9:44:30 AM(UTC)
sjalloq

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So what voltage are you feeding in? All the calcs/estimates I've done so far suggest that the reg will either drop out or run too hot.

With two relay boards I calculated a full load current of 352mA. Add in the remaining components and you're looking at about 500mA aren't you? With only a 220uF capacitor won't you have massive ripple?

Maybe my calcs are off but I'd like to understand. Cheers.

[Edit: maybe I should give some values.

I was planning on using a 15VA transformer with 9V secondaries and a secondary current of 0.83A. ]

Edited by user Monday, June 15, 2009 9:47:25 AM(UTC)  | Reason: Not specified

Russ White  
#5 Posted : Monday, June 15, 2009 9:50:34 AM(UTC)
Russ White

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In practice it works just fine. :)

The ripple before the reg is actually not that important in this case.

If I were driving more than 2 relays boards I would probably make that cap 1000uf.

Cheers
Russ
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